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If user want to use clone ++ to clone a bug from Project source “Project A” to project destination “Project B”, any status update from the cloned bug (in ProjectB) should sync automatically to parent bug (in source project Project A) and the comments should automatically sync in both way.

Note: In the above scenario consider that they are having different WFs and mandatory fields in destination project(s).

See below screenshot of created diagram:

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    1 answer


      Hi Venkatesh Pokala

      Thanks for raising the request here - other users will benefit from it

      The way to bring a cloned issue under sync with its parent is

      1. Detect the fact that an issue has been cloned
      2. Retrieve the issue id of the parent and the child (parent is source, child is the cloned issue)
      3. connect both issues using the Exalate API

      Create a custom field 'ParentID' of type numeric

      Step 1 - detect the fact that an issue has been cloned

      This should be possible by tweaking the substitution variables as documented here
      Assume you add a custom field 'parent id' and set it whenever a clone happens.
      An Exalate trigger can then be used to bring the parent and child under sync

      The jql would be something like

      parentID is not empty

      Step 2 - retrieve the parent and child id

      In the connection which builds the twin (between parent and child), ensure that the parentid is contained in the replica

      // add following line in the outgoing sync of the connection, using the correct customfield name
      replica.customFields."ParentID" = issue.customFields."ParentID"

      By adding a custom field 'parent id', and setting it whenever a clone happens, the custom field will be able to trigger an exalate.

      Step 3 - connect parent and child

      By setting the in the incoming sync, exalate will not create an issue, but connect both items

      // do not create an issue but connect.  Assuming that the value is set
      if (firstSync) {    = replica.customFields."ParentID".value

      Have a chocolate (after validation)

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